Question

8man and 6 boys can finish a piece of work in one day while 2 man and 3 boys can finish it in 3 days find the time taken by one man alone and that by one boy alone to finish the work​

Answer 1

Answer:

therefore, 1 men and 1 boy can finish the work in 7.2 days.

Step-by-step explanation:

8 men and 6 boys can finish a piece of work in one day while 2men and 3boys can finish it in 3days . find the time taken by 1 men and one boy to finish the work .

let 1 man's 1 day's work = x , and 1 boy's 1 day's

work = y so then ,

8x + 6y = 1 / 1 -----------(1)

2x + 3y = 1 /3 -----------(2)

multiply equation (1) by 2 and eq(2) by 8

16x + 12y = 2 ------------(3)

16x + 24y = 8/ 3 --------(4)

-----------------------------subract.(3) and (4)

- 12y = [ 2 - (8/ 3) ]

-12y = - 2/ 3

y = 2 /36 => y = 1 /18

put value of 'y' in (1) we get

8x + 6 ( 1/ 18 ) = 1/ 1=> 8x = 1 - ( 6/ 18 )

8x = ( 3 - 1 )/ 3 = 2 / 3

8x = 2/ 3 =>x = 2 / 24 => x = 1 /12

(1man + 1boy)' s 1 days work

= [ ( ( 1 × 1) /12 ) + ( (1 × 1 )/ 18 ) ]

= ( 1/ 12) + ( 1/ 18 )

= (18 + 12 )/ 216 = 30 / 216 = 1 / 7.2

Answer 2

Step-by-step explanation:

Hi ye raha aapka answer

I hope it helps you