Math, asked by ap28542050411, 10 months ago

8men and 12boys can finish a piece of work in 10 days while 6 men and a voice can finish in 14 days find the time taken by one man alone and that one boy alarm to finish that work​

Answers

Answered by Siddharth4444
0

Answer:

Step-by-step explanation:

Let one man alone can finish the work in x days and one boy alone can finish the work in y days.

In one day man can do  

x

1

​  

th work , then 8 man can do  

x

8

​  

th part of work.

In one day man can do  

y

1

​  

th work , then 8 man can do  

y

12

​  

th part of work.

Given together they can finish in 10 days

∴  

x

8

​  

+  

y

12

​  

=  

10

1

​  

 

Again 6 man can do in one day =  

x

6

​  

 parts of the work.

Again 8 boy can do in one day =  

y

8

​  

 parts of the work.

Given that together they can finish in 14 days.

∴  

x

6

​  

+  

y

8

​  

=  

14

1

​  

 

Putting  

x

1

​  

=u  and    

y

1

​  

=v we get the following equations

8u+12v=  

10

1

​  

 

⇒80u+120v=1

And  

6u+8v=  

14

1

​  

 

⇒84u+112v=1

By Cross multiplication, we get  

⇒  

120−112

u

​  

=  

84−80

v

​  

=  

8960−10080

−1

​  

 

⇒  

8

u

​  

=  

4

v

​  

=  

−1120

−1

​  

 

⇒u=  

−1120

−8

​  

=  

140

1

​  

 

⇒v=  

−1120

−4

​  

=  

280

1

​  

 

Now u=  

140

1

​  

 =  

x

1

​  

 ⇒x=140

Now v=  

280

1

​  

 =  

y

1

​  

 ⇒y=280

Thus one man alone can finish work in 140 days and one boy alone can finish work in 280 days

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