Math, asked by kishoresow3302, 1 month ago

8men can complete a work in 4 days.6 women can complete the same work in 6 days.4 men &6 women started the work & worked for only 2 days then,how many women are required to complete the remaining work in one day? ​

Answers

Answered by SamikshaRathore
0

Answer:

5 days

Step-by-step explanation:

According to the question,

1 man = 2 women 

∴∴ 8 men + 4 women 

= (16 + 4) women = 20 women 

4 men + 8 women = 16 women 

20 women's 2 days' work 

= 26=1326=13 

Remaining work = 1 - 1313 = 2323

∵∵ 20 women complete 1 work in 6 days. 

∴∴ 16 women will do 2323 work in 

= 20×616×2320×616×23 = 5 days

Answered by s13712481
0

Step-by-step explanation:

1 man = 2 women

∴ 8 men + 4 women

= (16 + 4) women = 20 women

4 men + 8 women = 16 women

20 women's 2 days' work

= 26=13

Remaining work = 1 - 13 = 23

∵ 20 women complete 1 work in 6 days.

∴ 16 women will do 23 work in

= 20×616×23 = 5 days

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