Question

8men can do a work on 12 days .After 6days of work 4 men were added to finish the work when will the remaining work be completed

Answer 1

Answer:

by using the formula of M1D1=M2D2

8M*12=8M*6+12*x

96=48+12x

x=42 years agoHelpfull: Yes(3) No(0)

Total work= 96

For 6 days, 8 men do 8*6= 48 part of the work

Remaining work=96-48 i.e. 48

Now ,More 4 more men gets added to the work

So total number of men presently to do the work= 8+4=12 men

Therefore the remaining part of the work will be completed in 48/12= 4 days(Answer)1 year agoHelpfull: Yes(0) No(0) 1 day 1 man capacity =1/(8*12)

A/Q,

1=(6*8)/(8*12) + (12*x)/(8*12)

=> x=4