Question

8p^3-12/5 p^2+6/25 p-1/125


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Answer 1

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answer..

1

Multiply the numbers

8

3

−

1

⋅

1

2

5

2

+

6

2

5

⋅

−

1

⋅

1

1

2

5

8p^{3}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{12}{5}}}p^{2}+\frac{6}{25} \cdot p-1 \cdot \frac{1}{125}

8p3−1⋅512p2+256⋅p−1⋅1251

8

3

−

1

2

5

2

+

6

2

5

⋅

−

1

⋅

1

1

2

5

8p^{3}{\color{#c92786}{-\frac{12}{5}}}p^{2}+\frac{6}{25} \cdot p-1 \cdot \frac{1}{125}

8p3−512p2+256⋅p−1⋅1251

2

Combine multiplied terms into a single fraction

8

3

−

1

2

5

2

+

6

2

5

⋅

−

1

⋅

1

1

2

5

8p^{3}-\frac{12}{5}p^{2}+\frac{6}{25} \cdot p-1 \cdot \frac{1}{125}

8p3−512p2+256⋅p−1⋅1251

8

3

+

−

1

2

2

5

+

6

2

5

⋅

−

1

⋅

1

1

2

5

8p^{3}+\frac{-12p^{2}}{5}+\frac{6}{25} \cdot p-1 \cdot \frac{1}{125}

8p3+5−12p2+256⋅p−1⋅1251

3

Combine multiplied terms into a single fraction

8

3

+

−

1

2

2

5

+

6

2

5

−

1

⋅

1

1

2

5

8p^{3}+\frac{-12p^{2}}{5}+\frac{6}{25}p-1 \cdot \frac{1}{125}

8p3+5−12p2+256p−1⋅1251

8

3

+

−

1

2

2

5

+

6

2

5

−

1

⋅

1

1

2

5

8p^{3}+\frac{-12p^{2}}{5}+\frac{6p}{25}-1 \cdot \frac{1}{125}

8p3+5−12p2+256p−1⋅1251

4

Multiply the numbers

8

3

+

−

1

2

2

5

+

6

2

5

−

1

⋅

1

1

2

5

8p^{3}+\frac{-12p^{2}}{5}+\frac{6p}{25}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{125}}}

8p3+5−12p2+256p−1⋅1251

8

3

+

−

1

2

2

5

+

6

2

5

−

1

1

2

5

8p^{3}+\frac{-12p^{2}}{5}+\frac{6p}{25}{\color{#c92786}{-\frac{1}{125}}}

8p3+5−12p2+256p−1251

Solution

8

3

+

−

1

2

2

5

+

6

2

5

−

1

1

2

5

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