Math, asked by lakshmanakumarmedidi, 8 months ago

8p3+12/5p2+6/25p+1/125​

Answers

Answered by tretheboss07
1

Answer:

(10p−1) 3

125

Step-by-step explanation:

  1000p3 - 300p2 + 30p - 1

can be divided with  10p - 1

Polynomial Long Division :

10.10    Polynomial Long Division

Dividing :  1000p3 - 300p2 + 30p - 1

                             ("Dividend")

By         :    10p - 1    ("Divisor")

dividend     1000p3  -  300p2  +  30p  -  1

- divisor  * 100p2     1000p3  -  100p2        

remainder      -  200p2  +  30p  -  1

- divisor  * -20p1      -  200p2  +  20p    

remainder             10p  -  1

- divisor  * p0             10p  -  1

remainder                0

Quotient :  100p2-20p+1  Remainder:  0

Trying to factor by splitting the middle term

10.11     Factoring  100p2-20p+1

The first term is,  100p2  its coefficient is  100 .

The middle term is,  -20p  its coefficient is  -20 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   100 • 1 = 100

Step-2 : Find two factors of  100  whose sum equals the coefficient of the middle term, which is   -20 .

     -100    +    -1    =    -101

     -50    +    -2    =    -52

     -25    +    -4    =    -29

     -20    +    -5    =    -25

     -10    +    -10    =    -20    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -10  and  -10

                    100p2 - 10p - 10p - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   10p • (10p-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (10p-1)

Step-5 : Add up the four terms of step 4 :

                   (10p-1)  •  (10p-1)

            Which is the desired factorization

Multiplying Exponential Expressions:

10.12    Multiply  (10p-1)  by  (10p-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (10p-1)  and the exponents are :

         1 , as  (10p-1)  is the same number as  (10p-1)1

and   1 , as  (10p-1)  is the same number as  (10p-1)1

In our case, the common base is  (10p-1)  and the exponents are :

         2

and   1 , as  (10p-1)  is the same number as  (10p-1)1

The product is therefore,  (10p-1)(2+1) = (10p-1)3

Final result :

 (10p - 1)3

 ——————————

    125

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