Question

8pq² ( 2p²q -- 3p + 5q ) + 7pq if p = 1.7 and q= 0.4


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Answer 1

$8p {q}^{2} (2 {p}^{2q} - 3p + 5q + 7pq^{2} )$

So we will put the value of p = 1.7 and q = 0.4 in place of p and q

$8 \times 1.7 \times (0.4) ^{2}( ( {2 \times 1.7)}^{2 \times 0.4} - 3 \times 1.7 + 5 \times 0.4 + 7(1.7)(0.4) ^{2} )$

$13.6 \times 0.16( {3.4}^{0.8} - 5.1 + 2 + 11.9 \times 0.1613.6×0.16$

2.176(2.66 - 5.1 + 2 + 1.904)

$2.176 \times 1.464$

3.703104

The answer is 3.703104

Answer 2

Answer:

$8p {q}^{2} (2 {p}^{2} q - 3p + 5q) + 7pq$

$p = 1.7$

$q = 0.4$

$(8 \times 1.7 \times {0.4}^{2} )(2 \times {1.7}^{2} \times 0.4 - 3 \times 1.7 + 5 \times 0.4) + 7 \times 0.4 \times 1.7$

$(8 \times 1.7 \times 0.16)(2 \times 2.89 \times 0.4 - 3 \times 1.7 + 5 \times 0.4) + 7 \times 0.4 \times 1.7$

$2.176(2.312 - 5.1 + 2) + 4.76$

$2.176 \times ( - 0.788) + 4.76$

$( - 1.714688) + 4.76$

$3.045312$

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