Question

8root X / X+3 - root X / X+3 = 2 what is the value for x???

Answer 1

$\land=and,\ \ \lor=or\\\frac{x}{x+3}\ge0\ \ \land\ \ x\ne-3\Longleftrightarrow({x}\ge0\land{x}\ \textgreater \ -3)\lor(x\ \textless \ 0\land{x}\ \textless \ -3)\Longleftrightarrow\\\\x\ge0\ \lor\ {x}\ \textless \ -3\\\\8\sqrt{\frac{x}{x+3}}- \sqrt{\frac{x}{x+3}}=2\\\\7\sqrt{\frac{x}{x+3}}=2\ \ \ \ /^2\\\\49\cdot\frac{x}{x+3}=4\\\\\frac{x}{x+3}=\frac4{49}\\\\49x=4x+12\\45x=12\\x=\frac{12}{45}=\frac{4}{15}\\\\\textrm{The answer is OK, because:}\\\frac{4}{15}\ge0$