Question

8sec²theta-8tan²theta​

Answer 1

Step-by-step explanation:

$8 \sec {}^{2} - 8 \tan {}^{2} \\ 8( \sec {}^{2} - \tan {}^{2} ) \\ by \: identity \: 1 + \tan {}^{2} = \sec {}^{2} \\ 1 = \sec {}^{2} - \tan {}^{2} \\ \\ 8 \times (1) \\ \\ 8 \times 1 \\ 8$

Answer 2

Answer:

8

Step-by-step explanation:

8(sec²theta) - 8(tan²theta)

8(sec²theta - tan²theta)

8(1-tan²theta - tan²theta) {1-tan²theta=sec²theta}

8(1)

8