Question

8sec²thita-8TAN²thita​

Answer 1

8sec²thita-8TAN²thita3

Answered by Guest on 2019-06-05 17:50:09 | Votes 3 | #

8 sec² ∅ + 2 cosec²∅

⇒ 8(1 + tan²∅) + 2(1 + cot²∅)

⇒ 8 + 2 + 8 tan²∅ + 2 cot²∅

The minimum value of a tan²∅ + b cot²∅ = 2√ab

⇒ 10 + 2√(8 × 2)

⇒ 10 + 2√16 = 18

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