Question

8sin^2x + 3 cos ^2x = 5 then cot x=?


hlw
please please give me the answer fast ....expert we're are you. .....​

Answer 1

Answer:+-$\sqrt{3/2}$

Step-by-step explanation:

8$sin^{2}$x+5$cos^{2}$x=5

8$sin^{2}$x+(8-5)$cos^{2}$x=5

8$sin^{2}$x+8$cos^{2}$x-5

8($sin^{2}$x+$cos^{2}$x)-5

8(1)-5$cos^{2}$x=5

-5$cos^{2}$x=5-8

-5$cos^{2}$x=-3

$cos^{2}$x=-3/-5

cosx=$+-\sqrt{3/5}$

sinx=$+-\sqrt{2/5}$

cotx= cosx/sinx

cotx= +-$\sqrt{3/2}$