Question

8t - 1 = 12t + 3
find the value of t
I am giving this for 11 points...answer should be worth it... and I will mark the brainliest if u give me the correct answer...
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Answer 1

Step-by-step explanation:

8t-1-12t-3

-4t-4=0

t=-1 OK friend this is urs answer OK

Answer 2

Answer:

Point A(4,3)

point B (X,5)

CENTER O (2,3)

DISTANCE BETWEEN A AND O

\sqrt{(4 - 2) {}^{2} + (3 - 3) {}^{2} } \\ \sqrt{(2 {)}^{2} } \\ distance \: between \: a \: and \: b \: is \: \\ 2 \: units

distance between B and O is

\sqrt{(x - 2) {}^{2} + (5 - 3) {}^{2} } = 2 \\ (x - 2) {}^{2} + (2) {}^{2} = (2) {}^{2} \\ {x}^{2} - 4x + 4 + 4 = 4 \\ {x}^{2} - 4x + 4 = 0 \\ (by \: factorization) \\ {x}^{2} - 2x - 2x + 4 = 0 \\ ............ \\ .....(x - 2)(x - 2) = 0 \\ value \: of \: x \: is \: 2

Step-by-step explanation:

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