Question

8taps of the same size fill a tank in 27 minutes if two taps go out of order how long would the remaining taps take to fill the tank

Answer 1

Hi there !

This is a question of direct and inverse proportions.

Follow this method

TAPS. 8. 6

Time(in min). 27 y2

Let x be the taps required

y be the time in minutes

It can be noticed that as the number of pipes required increase, the time taken to fill the tank decrease and vice versa

So,
x is inversely proportional to y

x1y1 = x2y2

$8 \times 27 = 6 \times y2$

$\frac{8 \times 27}{6} = y2$
y2 = 36

So,

36 minutes will be required

Answer 2

Answer:

36 minutes is answer .

I hope it's help you ❤✌