8th and 15th term of an arithmetic sequence are 32 and 102 respectively write the sequence?
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Step-by-step explanation:
let the initial term = a and common difference = d
given,
8th term = a + (8-1)d = a+7d = 32
=> a = 32 - 7d ----(1)
15th term = a + (15-1)d = a + 14d = 102
=> 32 - 7d + 14d = 102 [from(1)]
=> 7d = 102-32 = 70
=> d = 70/7 = 10
=> a = 32-7d = 32 - 7×10 = -38
the sequence is:
-38, -28, -18, -8, 2, 12, 22, 32, 42, .....
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