Question

8th grade exercise 12.1 question 7, part i
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Answer 1

"a = ${(\frac{-5}{9})}^{-5}$

=> ${a}^{-2} = {({(\frac{-5}{9})}^{-5})}^{-2}$

=> ${a}^{-2} = {\frac{-5}{9}}^{-5-2}$

=> ${a}^{-2} = {(\frac{-5}{9})}^{-7}$

=> ${a}^{-2} = {(\frac{9}{-5})}^{7}$

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Answer 2

Answer:

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