8th term of a sequence is 120 if common different is 4 find sequence
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Answer:
A.P. = 98 , 102 , 106 , 110 ..............
Step-by-step explanation:
8th term = 120
a + (8 - 1) 4 = 120
a + 28 = 120
a = 98
A.P. = 98 , 102 , 106 , 110 ..............
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