Question

8x+1,6x-1,3x+5 are in A. P. find value of x

Answer 1

$\textbf{Concept used:}$

$\text{If a, b and c are in A.P, then}$

$\bf\,b=\frac{a+c}{2}$

$\textbf{Given:}$

$\text{8x+1, 6x-1, 3x+5 are in A.P}$

$\textbf{To find:}\;x$

$\text{Since 8x+1, 6x-1, 3x+5 are in A.P, we have}$

$6x-1=\frac{8x+1+3x+5}{2}$

$2(6x-1)=11x+6$

$12x-2=11x+6$

$12x-11x=6+2$

$\implies\boxed{\bf\,x=8}$

$\therefore\textbf{The value of x is 8}$

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Answer 2

The value of x = 8

Given:

8x+1,6x-1,3x+5 are in A. P.

To find:

The value of x

Concept used:

In arithmetic progression common difference is same in all numbers.

Explanation:

In arithmetic progression common difference is same in all numbers.

So that Common difference =  (6x-1) - (8x+1) = (3x+5) - (8x+1)

(6x-1) - (8x+1) = (3x+5) - (6x-1)

2((6x-1)) = 3x+5 +8x +1

12x - 2 = 11x +6

12x -11x = 6+2

        x = 8

The value of x = 8

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