8x +12y =52 8x +10y =30
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8x +12y=52................(equation 1)
8x+10y=30..................(equation2)
Subtracting equation 2 from equation 1,we get :
8x-8x+12y-10y=52-30
2y=22
y=22÷2=11
Substituting y=11 in equation 1, we get:
8x+12(11)=52
8x+132=52
8x=52-132
8x=(-80)
x=(-80)÷8=(-10)
So the solution of the given equation is x=(-10) & y=12
8x+10y=30..................(equation2)
Subtracting equation 2 from equation 1,we get :
8x-8x+12y-10y=52-30
2y=22
y=22÷2=11
Substituting y=11 in equation 1, we get:
8x+12(11)=52
8x+132=52
8x=52-132
8x=(-80)
x=(-80)÷8=(-10)
So the solution of the given equation is x=(-10) & y=12
NiraliShah:
Sry y=11
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