Question

(8x-13)(8x+11) sec ls no 5 expansion formulae .question from JEEVANDEEP perfect practice series .mathematics workbook

Answer 1

Answer:

64x square+16x-143

Step-by-step explanation:

(x+a)(x+b)= x square+(a+b)8x+an

(8x)square+[(-13)+11]8x+(-13*11)

64x square+(-2)8x-143

64x square+16x-143

Answer 2

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