Question

8x+14y=4
-6x-7y=-10

solving systems of equations by elimination (please show the work/steps in your answer)

Answer 1

I don't know ok understand

Answer 2

$8x+14y = 4$

$8x = 4 - 14y$

$x = \frac{4 - 14y}{8}$

$x = \frac{2 - 7y}{4}$

now putting the value of 'x' in second equation

$-6 × \frac{2 - 7y}{4} - 7y = -10$

$\frac{-12 + 42y}{4} - 7y = -10$

$\frac{-6 + 21y}{2} - 7y = -10$

$\frac{-6 + 21y - 14y}{2} = -10$

$-6 + 7y = -20$

$7y = -14$

$y = \frac{-14}{7}$

$y = -2$

so putting the value of 'y' in the first equation

$8x + 14(-2) = 4$

$8x - 28 = 4$

$8x = 32$

$x = \frac{32}{8}$

$x = 4$

so value of x and y are

4 and -2