Question

(8x^2-15x)-(x^2-27x)=ax^2+bx
If the equation above is true for all values of x, what is the value of b-a ?

Answer 1

Step-by-step explanation:

here is the answer of this question

Answer 2

The value of b-a is 5.

Step-by-step explanation:

Given:

$(8x^{2} -15x)-(x^{2} -27x)=ax^{2} +bx$.

The equation above is true for all values of x.

To Find:

The value of b-a.

Solution:

As given - $(8x^{2} -15x)-(x^{2} -27x)=ax^{2} +bx$.

$(8x^{2} -15x)-(x^{2} -27x)=ax^{2} +bx$

$8x^{2} -x^{2} -15x +27x=ax^{2} +bx$

$7x^{2} +12x=ax^{2} +bx$

As given-the equation above is true for all values of x.

Since the equation is true for all values of x, so the coefficient each terms can be compared.

Comparing the coefficient of $x^{2}$,we get.

$a=7$

Comparing the coefficient of $x$,we get.

$b=12$

The value of b-a = $12-7=5$

Thus, the value of b-a is 5.

PROJECT CODE=SPJ#2