Question

8x^2-22x-21=0 find value of x.​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

8x^2-22x-21

Sum (b) = -22

Product (ac) =8×21=168

Then the numbe is 6×-28=-168

And the sum is 6-28=-22

Therefore

8x^2-22x-21=0

8x^2-28x+6x-21=0

Taking common

4x(2x-7) +3(2x-7)=0

(2x-7) and(4x+3)=0

Therefore

2x-7=0 and 4x+3=0

2x=7. And 4x=-3

or x=7/2 and x=-3/4