Question

8x^2-4 find the zero of this polynomial

Answer 1

Answer:

this is called as completing square method

Answer 2

it can be written as,

8x2+0x-4

4{(√2x)2-(1)2}

4(√2x+1) (√2x-1)

(√2x+1) (√2x-1) =0

(√2x-1) =0 , (√2x+1) =0

√2x-1=0

x=1/√2

√2x+1=0

x=-1/√2