8x^3-1/27y^3 factorise
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Answer: 8x^3-1/27y^3
= (2x)^3 - (1/3y)^3
= (2x-1/3y)[(2x)^2+(1/3y)^2+(2x)
(1/3y)]
= (2x-1/3y)(4x^2+1/9y^2+2/3xy)
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