Math, asked by hitarthbhatia, 7 months ago

8x^3-1/27y^3 factorise

Answers

Answered by ritvik86

17

Step-by-step explanation:

its yur solution dear....

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Answered by ahanatarafder06

15

Answer: 8x^3-1/27y^3

= (2x)^3 - (1/3y)^3

= (2x-1/3y)[(2x)^2+(1/3y)^2+(2x)

(1/3y)]

= (2x-1/3y)(4x^2+1/9y^2+2/3xy)

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