Question

8x^3-27 = (a-b) ( 4x^2+6x-9) find the value of ab​

Answer 1

$8*x^3+27-(4*x^2-6*x+9)=0$

$((8•(x3))+27)-((22x2-6x)+9) = 0$

$(23x3 + 27) - (4x2 - 6x + 9) = 0$

Answer 2

Answer:

$8 {x}^{3} - 27 = (a - b)(4 {x}^{2} + 6x - 9 \\ 8 {x}^{3} - 4 {x}^{2} + 6x = (a - b)(18) \\ 8 {x}^{3} - 4 {x}^{2} + 6x = 18a - 18b$

hope it helps you ✌️✅✅✅