Question

(8x^3 - 27y^3) ÷ (2x - 3y) is equal to​

Answer 1

Question :-

To find the value of --- (8x^3 - 27y^3) ÷ (2x - 3y)

Answer :-

● Taking numerator in -

(8x^3 - 27y^3) ÷ (2x - 3y)

⟹ 8x^3 - 27y^3

⟹ (2x) ^3 - (3y) ^3

Using identity ---

● a^3 - b^3 = ( x - y) ( x^2 + y^2 + xy)

⟹ ( 2x - 3y ) ( [2x]^2 + [3y]^2 + [2x][3y])

⟹ (2x - 3y) ( 4x^2 + 9y^2 + 6xy )

Substituting its expanded form in fraction ,

(2x - 3y) ( 4x^2 + 9y^2 + 6xy ) ÷ (2x - 3y)

■ (2x - 3y) will be cancelled .

■ 4x^2 + 9y^2 + 6xy is left.

☆ 4x^2 + 9y^2 + 6xy is the answer.

Hope it helps !