Math, asked by alokayesha01, 9 months ago

8x^3+27y^3 if 2x+3y=14and xy=8​

Answers

Answered by dharshinilatha
1

Answer:

8x^3+27y^3= 1988

Step-by-step explanation:

(2x+3y)^3= (2x)^3+(3y)^3 + 3*18(14)   ( (A+B)^3= A^3+B^3+3AB(A+B) )

  (14)^3    = 8x^3+27y^3 + 756

2744-756=8x^3+27y^3

8x^3+27y^3= 1988

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