Question

8x^3+27y^3 if 2x+3y=14andxy=8

Answer 1

Answer:

(2x)^3+(3y)^3=(2x+3y)((2x)^2-2x×3y+(3y)^2)

=(2x+3y)(4x^2-6xy+9y^2)

putting the values

=14 (4x^2-6×8+9y^2)

=14 (4x^2-48+9y^2)

56x^2-672+126y^2