Question

8x^3-27y/4x^2-9y^2 simplify​

Answer 1

Step-by-step explanation:

$\frac{8 {x}^{3} - 27 {y}^{3} }{4 {x}^{2} - 9 {y}^{2} } = \frac{(2x) ^{3} - ( {3y})^{3} }{ (2x)^{2} - (3y) ^{2} }$

$= \frac{(4 {x}^{2} + 6xy + 9 {y}^{2}) }{(2x + 3y)}$

$= \frac{(2x - 3y)(4 {x}^{2} + 6xy +9 {y}^{2} ) }{(2x - 3y)(2x + 3y)}$

it is simplest form