Math, asked by Snehasd, 4 months ago

8x-3/3x=2 find the value of x​

Answers

Answered by sangootiwari
0

Answer:

8x-3/3x=2

8x-3=6x

8x-6x=3

2x=3

x=3/2

The value of x is 3/2

OR

8x-3/3x=2

8x- 1/x=2

8x^2 -1=2x

8x^2-2x-1=0

8x^2-4x+2x-1=0

4x(2x-1)+1(2x-1)=0

(4x+1)(2x-1)=0

x=-1/4 or x=1/2

hope it's helpful for you

Answered by dasj19126
0

Step-by-step explanation:

8x -  \frac{3}{3x}  = 2

or,

8x -  \frac{1}{x}  = 2

or,

8 {x}^{2}  - 1 = 2x

or,

8 {x}^{2}  - 2x - 1 = 0

or,

8 {x}^{2}  - 4x + 2x - 1 = 0

or,

4x(2x - 1) +  1(2x - 1) = 0or,

(2x - 1)(4x + 1) = 0

or,

2x - 1 = 0

x =  \frac{1}{2}

or,,

4x + 1 = 0

x =  \frac{ - 1}{4}

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