Question

(√8x+33)-3=2√2x pls no spamming​

Answer 1

Answer:

Explanation:Original equation

√8x+33-3 = 2√2x

Isolate

√8x+33 = 3+2√2x

STEP

2

:

Eliminate the radical on the left hand side

Raise both sides to the second power

(√8x+33)2 = (3+2√2x)2

After squaring

8x+33 = 8x+9+12√2x

STEP

3

:

Get remaining radical by itself

Current equation

8x+33 = 8x+9+12√2x

Isolate radical on the left hand side

-12√2x = -8x-33+8x+9

Tidy up

12√2x = 24

STEP

4

:

Eliminate the radical on the left hand side

Raise both sides to the second power

(12√2x)2 = (24)2

After squaring

288x = 576

STEP

5

:

Solve the linear equation

Rearranged equation

288x -576 = 0

Add 576 to both sides

288x = 576

Divide both sides by 288

A possible solution is :

x = 2

STEP

6

:

Check that the solution is correct

Original equation, root isolated, after tidy up

√8x+33 = 3+2√2x

Plug in 2 for x

√8•(2)+33 = 3+2√2•(2)

Simplify

√49 = 7

Solution checks !!

Solution is:

x = 2