8x_3y=12
5x_7y=_13 by substitution method
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Answer:
8x-3y=12
8x=3y+12
x=(3y+12)/8 ..........(i)
5x-7y=-13
Putting eq(i)
5(3y+12/8)-7y= -13
(15y+60)/8-7y=-13
(15y+60-56y)/8= -13
15y+60-56y= -104 [Cross multiplying]
-41y= -104-60
-41y= -164
41y=164
y=164/41
y=4
Putting value of y
8x-3y=12
8x-3(4)=12
8x-12=12
8x=12+12
8x=24
x=24/8
x=3
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