Math, asked by kimm1216, 10 months ago

8x_3y=12
5x_7y=_13 by substitution method

Answers

Answered by ammusaadkhan
1

Answer:

8x-3y=12

8x=3y+12

x=(3y+12)/8 ..........(i)

5x-7y=-13

Putting eq(i)

5(3y+12/8)-7y= -13

(15y+60)/8-7y=-13

(15y+60-56y)/8= -13

15y+60-56y= -104 [Cross multiplying]

-41y= -104-60

-41y= -164

41y=164

y=164/41

y=4

Putting value of y

8x-3y=12

8x-3(4)=12

8x-12=12

8x=12+12

8x=24

x=24/8

x=3

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