Question

8x +4=3(x-1)+7
5t-3= 3t-5

Answer 1

u need x and t values right
8x+4=3x-3+7
8x-3x=4-4
5x=0
x=0
and
5t-3=3t-5
5t-3t=-5+3
2t=-2
t=-1
and therefore,
x=0
t=-1

Answer 2

Hello friends!!

Here is ur answer :

I)

$8x + 4 = 3(x - 1) + 7$


$8x + 4 = 3x - 3 + 7$


$8x + 4 = 3x + 4$


$8x - 3x = + 4 - 4$

$5x = 0$


$x = \frac{0}{5}$



$x = 0$

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II)

$5t - 3 = 3t - 5$


$5t - 3t = - 5 + 3$


$2t = - 2$


$t = \frac{ - 2}{2}$


$t = - 1$


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HOPE IT HELPS YOU...