Question

8x+4y=2
find three suitable value for x and y​

Answer 1

✴️ SOLUTION :-

As three cases will be...

(1) if x = 1

Then, 8×1 + 4y = 2

=> 4y = 2 - 8

=> y = -6/4

=> y = -3/2

(2) if x = 2

Then, 8×2 + 4y = 2

=> 4y = 2 - 16

=> y = -14/4

=> y = -7/2

(3) if x = 3

Then, 8×3 + 4y = 2

=> 4y = 2 - 24

=> y = -22/4

=> y = -11/2

these are required three values for x and y...

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Answer 2

Answer:

x=1/4 y=1/2

x=1/2 y=0

x=0 y=1

Step-by-step explanation: