Question

8x+7y=11 and 7x+8y=4​

Answer 1

Answer:

x = 4 and y = -3

I HOPE IT'S HELPFUL

Answer 2

Answer:

x=4

y= -3

Step-by-step explanation:

8x+7y=11

8x=11-7y

x=

$\frac{11 - 7y}{8}$

Putting this value of X in eq.2

7x+8y=4

$7( \frac{11 - 7y}{8} ) + 8y = 4$

$\frac{77 - 49y}{8} + 8y = 4$

$\frac{77 - 49y + 64y}{8} = 4$

$77 + 15y = 32$

$15y = 32 - 77$

$y = \frac{ - 45}{15} = - 3$

x=

$\frac{11 - 7y}{8} = \frac{11 - 7( - 3)}{8} = \frac{11 + 21}{8} = \frac{32}{8} = 4$

Therefore x=4

y= -3

Hope my answer helps you if yes then pls mark my answer as brainliest.