Math, asked by bk9953947470, 1 year ago

8x cube minus bracket 2x minus y bracket close whole cube

Answers

Answered by yuvsingh1705
14

8 {x}^{3}  -  {(2x - y)}^{3}  \\  = 8 {x}^{3}  - ( {(2x)}^{3}  - {(y)}^{3}  - 3(2x)(y)(2x - y) \\  = 8 {x}^{3}  - (8 {x}^{3}  -  {y}^{3}  - 12 {x}^{2} y + 6x {y}^{2}) \\  = 8 {x}^{3}  - 8 {x}^{3}  +  {y}^{3}  + 12 {x}^{2} y - 6x {y}^{2}  \\   = {y}^{3}  + 12 {x}^{2}  + 6x {y}^{2}
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Answered by Mausam11
5
8x^3-(2x-y)^3

a^3-b^3=(a-b)(a^2+ab+b^2)

where a=2x, b=2x-y

(2x)^3-(2x+y)^3

(2x-2x+y){4x^2+2x(2x-y)+(2x-y)^2}

y{4x^2+4x-2xy+4x^2+y^2-4xy}

y(8x^2+4x-6xy+y^2)

8yx^2+4xy-6xy^2+y^3

y^3+8yx^2-6xy^2+4xy

........:-)
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