Question

8x2-26x+15 factorize the following​

Answer 1

Answer:

hope this is helpful for you

Answer 2

$\huge\mathcal\colorbox{teal}{{\color{black}{ᴀɴSᴡᴇʀ~~~↓}}}$

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$\large\bf\color{navy}{To~factorise:}$

$\tt{8x^{2}-26x+15=0}$

$\bf\color{navy}{Here;~S=-26~~P=120~~~(-6,-20)}$

$\tt{→(8x^{2}-6x)+(-20x+15)=0}$

$\tt{→[2x(4x-3)~]+[-5(4x-3)~]=0}$

$\tt{→(4x-3)(2x-5)=0}$

$\tt{→4x-3=0~~or~~2x-5=0}$

$\tt{→x={\frac{3}{4}}~~or~~x={\frac{5}{2}}}$

$\large\bf{\therefore~The~roots~are:~{\frac{3}{4}}~and~{\frac{5}{2}}}$

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$\huge\sf\color{teal}{ʜᴏᴘᴇ~ɪᴛ~ʜᴇʟᴘs..!!}$