Question

8x²+2x-1 full answer for this question ​

Answer 1

$\large\fbox\red{Answer}$

$\sf\:8 {x}^{2} + 2x - 1$

$\sf⟹\: 8 {x}^{2} + (4 - 2)x - 1$

$\sf⟹\: 8 {x}^{2} + 4x - 2x - 1$

$\sf⟹\: 4x(2x + 1) - 1(2x + 1)$

$\sf⟹\: (4x - 1)(2x - 1)$

$\sf\:Either\:4x-1=0$

$\sf⟹\:4x=1$

$\tt\purple{⟹x=\frac{1}{4}}$

$\sf\:oR\:2x-1=0$

$\sf⟹\:2x=1$

$\tt\purple{⟹\:x=\frac{1}{2}}$

• Thnku ❣

Answer 2

$\huge\rm\color{red}{{\mathcal{A}}n{\mathcal{S}}w{\mathcal{E}}r:}$

${}$

$\bf{{\underline{To~factorise}}:}$

$\tt{~~~~~~~~8x^{2}+2x-1}$

$\color{red}{\boxed{\sf S=2~,~~P=-8~~~~(4~,~-2)}}$

$\tt\longmapsto{(8x^{2}+4x)+(-2x-1)}$

$\tt\longmapsto{[4x(2x+1)~]+[-1(2x+1)~]}$

$\tt\longmapsto{(4x-1)(2x+1)}$

$\bf\therefore{{\underline{The~factors~are}}:}$

$~~~~~~~~{ \color{red}{ \underline{ \boxed{ \bf4x- 1}}}}\: \: \: \: { \sf{and}} \: \: \: \: { \color{red}{ \underline{ \boxed{ \bf 2x + 1}}}}$