Question

8x²-4 ,,,,,,, please solve step by step showing the process and tell the zeros of this polynomial?​

Answer 1

Answer:

8x²-4. =4(2x²-1²). =4(√2x+1)(√2x-1). X=1/√2,-1/√2

Answer 2

Answer:

1 Answer

1. We have:
2. f(x) = 8x2 ˗ 4.
3. It can be written as 8x2 + 0x ˗ 4.
4. = 4 { (√2x)2 ˗ (1)2 }
5. = 4 (√2x + 1) (√2x ˗ 1)
6. ∴ f(x) = 0 ⇒ (√2x + 1) (√2x ˗ 1) = 0.
7. ⇒ (√2x + 1) = 0 or √2x ˗ 1 = 0.
8. ⇒ x = −1/√2 or x = 1/√2.

Explanation:

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