8x²-9 sum and product of the zeroes of given polynomial
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Answer:
sum of zeros=0
product of zeros= -9/8
Step-by-step explanation:
let,f(x)=8x²+0x+(-9) ---(general form ax²+bx+c)
if two roots of f(x) is α and β
then α+β= -b/a= 0 and αβ=c/a= -9/8
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