(8x²-y³) (3xy-2 x) find the product of algebric expression
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Answered by
1
Answer:
Given, 8x^3 - (2x - y) ^3
= (2x)^3 - (2x - y) ^3
Using the formula:
a^3 - b^3= (a - b)(a^2 + ab + b^2). (1)
Putting the value of a = 2x, b =
the above formula; we get
= (2x - (2x+y)) {(2x)^2 - 2x*(2x - y) + (2x - y) ^2}
= y {(4x^2 - 4x^2 + 2xy + 4x^2 - 4xy + y^2)}
= y (4x^2 - 2xy + y^2)
= (2x - y) in
eq.
Therefore, factorized form of the given problem is y (4x^2 - 2xy + y^2).
Step-by-step explanation:
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