Math, asked by vankdavathjaganjaga, 1 year ago

8x³+y³+z³-6xyz+factorise

Answers

Answered by ritu16829
3

Answer:

8x^3+y^3+z^3-6xyz

(2x)^3+(y)^3+(z)^3-3(2x)(y)(z)

now remember the identity....

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

so factors are...

(2x+y+z)(4x^2+y^2+z^2-2xy-yz-2zx)

hope it works

plz mark it as brainliest answer

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