8x³+y³+z³-6xyz+factorise
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Answer:
8x^3+y^3+z^3-6xyz
(2x)^3+(y)^3+(z)^3-3(2x)(y)(z)
now remember the identity....
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
so factors are...
(2x+y+z)(4x^2+y^2+z^2-2xy-yz-2zx)
hope it works
plz mark it as brainliest answer
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