Question

8x³+y³+z³-6xyz factorise

Answer 1

8xcube + y cube + z cube - 6 xyz
(2x) cube + (y) cube + (z) cube -3(2x)(y)(z)
By using identity
(2x + y + z) [(2x)square +(y) square +(z) square - (2x)(y)+(y)(z)+(z)(2x)]
(2x+y+z)(4x square + y square + z square - 2xy + yz + 2zx