Question

(8x⁴+10x³-5x²-4x+1) (2x²+x+1)​

Answer 1

Answer:

GIVEN :

Divide the polynomial (8x⁴+10x³-5x²-4x+1) by the polynomial (2x²+x-1)

TO FIND :

The remainder and quotient for the given polynomial.

SOLUTION :

Given that divide the polynomial (8x⁴+10x³-5x²-4x+1) by the polynomial (2x²+x-1)

4x^2+3x-24x 2 +3x−2

____________________

2x²+x-1 ) 8x⁴+10x³-5x²-4x+1

8x^4+4x^3-4x^28x 4 +4x 3−4x 2

_(-)__(-)___(+)__________

6x^3-x^2-4x6x 3−x 2 −4x

6x^3+3x^2-3x6x 3 +3x 2 −3x

_(-)__(-)__(+)______

-4x^2-x+1−4x 2−x+1

-4x^2-2x+2−4x 2 −2x+2

_(+)__(+)__(-)__

x-1

_____________

The quotient is 4x^2+3x-24x 2+3x−2 and remainder is x-1 when the given polynomial (8x⁴+10x³-5x²-4x+1) is divided by the polynomial (2x²+x-1).

∴ The quotient is 4x^2+3x-24x

2

+3x−2 and remainder is x-1.

Step-by-step explanation:

$\huge \sf {\purple {\underline {\purple{\underline {❥B•T•S࿐ }}}}}$

Answer 2

Answer:

Question:

(8x⁴+10x³-5x²-4x+1) (2x²+x+1)

Solution:

(8x⁴+10x³-5x²-4x+1) (2x²+x+1)

16x⁶+8x⁴+8x⁴20x⁵+10x⁴+10x³-10x⁴-5x²-8x³-4x+2x²+x+1

16x⁶+28x⁵+8x⁴-3x³-7x²-3x+1

Answer:

16x⁶+28x⁵+8x⁴-3x³-7x²-3x+1

Step-by-step explanation:

hope it helps you.