Question

(8x⁴+10x³-5x²-4x+1)by(2x²+x-1)​

Answer 1

just do divide

.... or nothing okay.

Answer 2

Answer:

divide the polynomial (8x⁴+10x³-5x²-4x+1) by the polynomial (2x²+x-1)

4x^2+3x-24x

2

+3x−2

____________________

2x²+x-1 ) 8x⁴+10x³-5x²-4x+1

8x^4+4x^3-4x^28x

4

+4x

3

−4x

2

_(-)__(-)___(+)__________

6x^3-x^2-4x6x

3

−x

2

−4x

6x^3+3x^2-3x6x

3

+3x

2

−3x

_(-)__(-)__(+)______

-4x^2-x+1−4x

2

−x+1

-4x^2-2x+2−4x

2

−2x+2

_(+)__(+)__(-)__

x-1

_____________

The quotient is 4x^2+3x-24x

2

+3x−2 and remainder is x-1 when the given polynomial (8x⁴+10x³-5x²-4x+1) is divided by the polynomial (2x²+x-1).

∴ The quotient is 4x^2+3x-24x

2

+3x−2 and remainder is x-1