Question

மீ பொ வா காண்க 8x4y²,48x²y⁴​

Answer 1

Answer:

Correct option is

B

25.5 m/sec

Let the acceleration of the car is =a and the distance between A and B is =d

v

2

−u

2

=2ad

Given,

v=30m/s and u=20m/s

2ad=30

2

−20

2

ad=

2

(900−400)

=250

when the car is at the mid point of AB then let the speed of the car is

v

1

v

1

2

−20

2

=2a(

2

d

)

v

1

2

=ad+400=250+400=650

therefore

v

1

is =25.5m/s