8xcube + 12x sqaure + 6x + 1
Answers
Answer:
8x3+12x2+6x+1=0
One solution was found :
x = -1/2 = -0.500
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((8 • (x3)) + (22•3x2)) + 6x) + 1 = 0
Step 2 :
Equation at the end of step 2 :
((23x3 + (22•3x2)) + 6x) + 1 = 0
Step 3 :
Checking for a perfect cube :
3.1 Factoring: 8x3+12x2+6x+1
.
8x3+12x2+6x+1 is a perfect cube which means it is the cube of another polynomial
In our case, the cubic root of 8x3+12x2+6x+1 is 2x+1
Factorization is (2x+1)3
Equation at the end of step 3 :
(2x + 1)3 = 0
Step 4 :
Solving a Single Variable Equation :
4.1 Solve : (2x+1)3 = 0
(2x+1) 3 represents, in effect, a product of 3 terms which is equal to zero
For the product to be zero, at least one of these terms must be zero. Since all these terms are equal to each other, it actually means : 2x+1 = 0
Subtract 1 from both sides of the equation :
2x = -1
Divide both sides of the equation by 2:
x = -1/2 = -0.500
One solution was found :
x = -1/2 = -0.500
Answer:
madam/sir pls can u type the after question so that I can answer u
because I am getting confused wether we should factorise or wt so ok