Question

8xy (x^2 + y^2) - solve this than(x+y)=5 and (x-y)=1​

Answer 1

Formula of x² + y² =

$x ^{2} + y ^{2} = (x + y )(x - y)$

As (x + y) = 5

(x - y) = 1

Solution

= 8xy (5)(1)

= 8xy × 5

= 40xy

This is the correct answer of your question

Mark as brainliest please

Answer 2

Answer:

200xy

Step-by-step explanation:

is answer ok bhaiya please don't forget to mark BRAINLIST.