Math, asked by suryanshmishra124, 8 months ago

8y^2-3y , find the Zeroes of the given polynomial. please write in step

Answers

Answered by fidhafiros9

0

Answer:

Step-by-step explanation:

8y^2-3y

8y2 - 3y = y • (8y - 3)

y(8y-3)=0

8y-3=0/y

y=3/8

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