(8y+3x)^3-(3x-8y)3=?
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Answered by
7
Answer:
a³ - b³ = (a-b) (a² + ab + b²)
According to the question,
= [(8y+3x) - (3x - 8y)][(8y + 3x)² + (8y + 3x)(3x - 8y) + (3x - 8y)²]
= [16y][64y² + 48xy + 9x² + 9x² - 64y² +9x² - 48xy + 64y²]
= (16y)(64y² + 27x²)
= 1024y³ + 432x²y
Answered by
2
Answer:
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